CSS - PMS - CCE - PCS - Mathematics
Age Problems
A is 6 years younger than B. Five years from now, the sum of their ages will be 50. What is A's present age?
A. 22
B. 18
C. 15
D. 17
Correct Answer: D
Present sum=50−10=40. Let A=x and B=x+6. Then 2x+6=40, so x=17.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A person's age after 15 years will be four times the age 15 years ago. What is the present age?
A. 30
B. 25
C. 35
D. 20
Correct Answer: B
Let present age=x. x+15=4(x−15). Therefore x+15=4x−60, 3x=75, x=25.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The ages of A, B and C are in the ratio 4:5:6. If C is 14 years older than A, what is B's age?
A. 28
B. 32
C. 42
D. 35
Correct Answer: D
C−A=2 parts=14, so one part=7. B=5×7=35.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A father is 28 years older than his son. Four years ago, he was three times as old as his son. What is the son's present age?
A. 16
B. 20
C. 18
D. 14
Correct Answer: C
Let son's age=x; father=x+28. Four years ago: x+24=3(x−4). Thus x=18.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The sum of two present ages is 50 years. After 5 years, the older person will be twice the younger. What is the younger person's present age?
A. 25
B. 15
C. 10
D. 20
Correct Answer: B
Let younger=x and older=50−x. After 5 years: 55−x=2(x+5). Thus 45=3x and x=15.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Six years ago, the ages of A and B were in the ratio 1:2. Six years from now, they will be in the ratio 2:3. What is B's present age?
A. 24
B. 36
C. 28
D. 30
Correct Answer: D
Six years ago ages were x and 2x. Present ages are x+6 and 2x+6. After six more years, (x+12)/(2x+12)=2/3, giving x=12; B=30.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The present ages of A and B are in the ratio 3:2. After 10 years, their ages will be in the ratio 4:3. What is A's present age?
A. 20
B. 24
C. 36
D. 30
Correct Answer: D
Let ages be 3x and 2x. (3x+10)/(2x+10)=4/3. Thus 9x+30=8x+40, x=10 and A=30.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
In 8 years, a person's age will be 1.5 times the present age. What is the present age?
A. 16
B. 12
C. 18
D. 24
Correct Answer: A
Let present age=x. x+8=1.5x, so 0.5x=8 and x=16.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The ages of two people are in the ratio 5:3 and differ by 14 years. What is the older person's age?
A. 35
B. 42
C. 28
D. 30
Correct Answer: A
Difference of ratio parts=2. One part=14/2=7. Older age=5×7=35.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Twelve years ago, a father was five times as old as his son. Presently, he is three times as old. What is the son's present age?
A. 18
B. 24
C. 30
D. 20
Correct Answer: B
Let son's age=x and father=3x. Twelve years ago: 3x−12=5(x−12). Solving gives x=24.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A person's age after 10 years will be twice the present age. What is the present age?
A. 5
B. 10
C. 20
D. 15
Correct Answer: B
Let present age be x. x+10=2x, so x=10 years.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The average age of five workers is 32 years. A 40-year-old worker leaves and the new average becomes 30 years. What is the age of the replacement?
A. 28
B. 34
C. 32
D. 30
Correct Answer: D
Original total=160. After removing 40, total=120. Required total for five at average 30 is 150, so replacement=30.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The average age of six family members is 25 years. A child is added and the average becomes 22 years. What is the child's age?
A. 4
B. 5
C. 7
D. 2
Correct Answer: A
Original total=6×25=150. New total=7×22=154. Child's age=154−150=4 years.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The ages of three persons are in the ratio 2:3:4 and total 72 years. What is the oldest person's age?
A. 24
B. 36
C. 32
D. 28
Correct Answer: C
Total parts=9. One part=72/9=8. Oldest age=4×8=32 years.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The present ages of A and B are in the ratio 7:9. After 6 years, the ratio will be 4:5. What is B's present age?
A. 42
B. 60
C. 48
D. 54
Correct Answer: D
Let ages be 7x and 9x. (7x+6)/(9x+6)=4/5. So 35x+30=36x+24, x=6 and B=54.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A mother is five times as old as her daughter. After 10 years, she will be three times as old. What is the mother's present age?
A. 50
B. 60
C. 40
D. 45
Correct Answer: A
Let daughter's age be x; mother=5x. After 10 years: 5x+10=3(x+10). Thus 2x=20, x=10 and mother=50.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A is 8 years older than B. Four years ago, A was twice as old as B. What is A's present age?
A. 18
B. 20
C. 24
D. 16
Correct Answer: B
Let B's present age be x, so A=x+8. Four years ago: x+4=2(x−4). Hence x=12 and A=20.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
After 6 years, the ages of A and B will be in the ratio 5:6. Their present age difference is 4 years. What is A's present age?
A. 18
B. 14
C. 16
D. 12
Correct Answer: B
Age difference remains 4. Future ages 5x and 6x differ by x=4. A's future age=20, so present age=20−6=14.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Five years ago, the ages of A and B were in the ratio 3:4. Their present ages total 45 years. What is B's present age?
A. 24
B. 20
C. 30
D. 25
Correct Answer: D
Five years ago ages were 3x and 4x. Present ages are 3x+5 and 4x+5. So 7x+10=45, x=5 and B=4(5)+5=25.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The present ages of A and B are in the ratio 4:5, and their sum is 54 years. What is A's age?
A. 24
B. 26
C. 20
D. 30
Correct Answer: A
Total ratio parts = 4 + 5 = 9. One part = 54/9 = 6. Therefore A = 4 × 6 = 24 years.