CSS MPT 2027 Complete Preparation Pack 12 Premium PDFs • 8 Live Mock Exams Explore Pack
CSS - PMS - CCE - PCS - Mathematics Practice

Analytical Reasoning MCQs

Practice important Analytical Reasoning MCQs with answers, explanations, theory links, and exam-focused preparation.

Which option best explains your concept?
Instant answer validation
Performance tracking
Timed mock tests

Step-by-Step

Detailed Explanations

54,554

Practice MCQs

27

Mock Tests

95%

Success Focus

Analytical Reasoning

Analytical Reasoning MCQs With Answers

Only MCQs mapped to Analytical Reasoning are shown on this page. You are viewing page 2.

Find Your Question Instantly

Search by keyword, subject, topic, or exact MCQ text.

CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates F, G, K, S, V, X must be divided into two teams of three. X must be on the same team as V; S must be on the same team as X. G must be on the same team as F; K must be on the same team as G. Which division is valid?
A. Team A: X,S,G; Team B: V,F,K
B. Team A: X,G,F; Team B: V,S,K
C. Team A: X,V,S; Team B: G,F,K
D. Team A: X,V,G; Team B: S,F,K
Correct Answer: C
The rules require exactly the groups {X,V,S} and {G,F,K}.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates F, G, K, S, V, X must be divided into two teams of three. X must be on the same team as V; S must be on the same team as X. G must be on the same team as F; K must be on the same team as G. If G is in Team 2, which two candidates must also be in Team 2?
A. X and V
B. V and S
C. S and F
D. F and K
Correct Answer: D
G, F, and K must be together.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates F, G, K, S, V, X must be divided into two teams of three. X must be on the same team as V; S must be on the same team as X. G must be on the same team as F; K must be on the same team as G. If X is assigned to Team 1, who else must be in Team 1?
A. F and K
B. G and F
C. S and G
D. V and S
Correct Answer: D
X, V, and S form an inseparable three-person team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates F, G, K, S, V, X must be divided into two teams of three. X must be on the same team as V; S must be on the same team as X. G must be on the same team as F; K must be on the same team as G. Which pair cannot belong to the same team?
A. X and G
B. V and S
C. G and F
D. X and V
Correct Answer: A
X belongs with V,S, while G belongs with F,K; therefore X and G are in different teams.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates F, G, K, S, V, X must be divided into two teams of three. X must be on the same team as V; S must be on the same team as X. G must be on the same team as F; K must be on the same team as G. Which set must form one complete team?
A. V, F, K
B. X, V, G
C. X, V, S
D. X, G, F
Correct Answer: C
Because X, V, and S must all be together and each team has three members, they form one team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates L, P, S, W, X, Y must be divided into two teams of three. P must be on the same team as X; Y must be on the same team as P. W must be on the same team as L; S must be on the same team as W. Which division is valid?
A. Team A: P,X,Y; Team B: W,L,S
B. Team A: P,X,W; Team B: Y,L,S
C. Team A: P,W,L; Team B: X,Y,S
D. Team A: P,Y,W; Team B: X,L,S
Correct Answer: A
The rules require exactly the groups {P,X,Y} and {W,L,S}.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates L, P, S, W, X, Y must be divided into two teams of three. P must be on the same team as X; Y must be on the same team as P. W must be on the same team as L; S must be on the same team as W. If W is in Team 2, which two candidates must also be in Team 2?
A. Y and L
B. L and S
C. P and X
D. X and Y
Correct Answer: B
W, L, and S must be together.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates L, P, S, W, X, Y must be divided into two teams of three. P must be on the same team as X; Y must be on the same team as P. W must be on the same team as L; S must be on the same team as W. If P is assigned to Team 1, who else must be in Team 1?
A. L and S
B. Y and W
C. X and Y
D. W and L
Correct Answer: C
P, X, and Y form an inseparable three-person team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates L, P, S, W, X, Y must be divided into two teams of three. P must be on the same team as X; Y must be on the same team as P. W must be on the same team as L; S must be on the same team as W. Which pair cannot belong to the same team?
A. W and L
B. P and X
C. X and Y
D. P and W
Correct Answer: D
P belongs with X,Y, while W belongs with L,S; therefore P and W are in different teams.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates L, P, S, W, X, Y must be divided into two teams of three. P must be on the same team as X; Y must be on the same team as P. W must be on the same team as L; S must be on the same team as W. Which set must form one complete team?
A. P, X, Y
B. X, L, S
C. P, X, W
D. P, W, L
Correct Answer: A
Because P, X, and Y must all be together and each team has three members, they form one team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates E, F, R, T, U, V must be divided into two teams of three. T must be on the same team as E; R must be on the same team as T. F must be on the same team as V; U must be on the same team as F. Which division is valid?
A. Team A: T,E,R; Team B: F,V,U
B. Team A: T,E,F; Team B: R,V,U
C. Team A: T,R,F; Team B: E,V,U
D. Team A: T,F,V; Team B: E,R,U
Correct Answer: A
The rules require exactly the groups {T,E,R} and {F,V,U}.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates E, F, R, T, U, V must be divided into two teams of three. T must be on the same team as E; R must be on the same team as T. F must be on the same team as V; U must be on the same team as F. If F is in Team 2, which two candidates must also be in Team 2?
A. E and R
B. T and E
C. V and U
D. R and V
Correct Answer: C
F, V, and U must be together.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates E, F, R, T, U, V must be divided into two teams of three. T must be on the same team as E; R must be on the same team as T. F must be on the same team as V; U must be on the same team as F. If T is assigned to Team 1, who else must be in Team 1?
A. E and R
B. F and V
C. R and F
D. V and U
Correct Answer: A
T, E, and R form an inseparable three-person team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates E, F, R, T, U, V must be divided into two teams of three. T must be on the same team as E; R must be on the same team as T. F must be on the same team as V; U must be on the same team as F. Which pair cannot belong to the same team?
A. T and E
B. E and R
C. T and F
D. F and V
Correct Answer: C
T belongs with E,R, while F belongs with V,U; therefore T and F are in different teams.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates E, F, R, T, U, V must be divided into two teams of three. T must be on the same team as E; R must be on the same team as T. F must be on the same team as V; U must be on the same team as F. Which set must form one complete team?
A. T, E, F
B. T, E, R
C. T, F, V
D. E, V, U
Correct Answer: B
Because T, E, and R must all be together and each team has three members, they form one team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates D, J, K, L, N, V must be divided into two teams of three. K must be on the same team as N; V must be on the same team as K. D must be on the same team as L; J must be on the same team as D. Which division is valid?
A. Team A: K,N,V; Team B: D,L,J
B. Team A: K,V,D; Team B: N,L,J
C. Team A: K,D,L; Team B: N,V,J
D. Team A: K,N,D; Team B: V,L,J
Correct Answer: A
The rules require exactly the groups {K,N,V} and {D,L,J}.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates D, J, K, L, N, V must be divided into two teams of three. K must be on the same team as N; V must be on the same team as K. D must be on the same team as L; J must be on the same team as D. If D is in Team 2, which two candidates must also be in Team 2?
A. N and V
B. V and L
C. K and N
D. L and J
Correct Answer: D
D, L, and J must be together.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates D, J, K, L, N, V must be divided into two teams of three. K must be on the same team as N; V must be on the same team as K. D must be on the same team as L; J must be on the same team as D. If K is assigned to Team 1, who else must be in Team 1?
A. N and V
B. D and L
C. L and J
D. V and D
Correct Answer: A
K, N, and V form an inseparable three-person team.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates D, J, K, L, N, V must be divided into two teams of three. K must be on the same team as N; V must be on the same team as K. D must be on the same team as L; J must be on the same team as D. Which pair cannot belong to the same team?
A. D and L
B. K and D
C. N and V
D. K and N
Correct Answer: B
K belongs with N,V, while D belongs with L,J; therefore K and D are in different teams.
CSS - PMS - CCE - PCS - Mathematics Analytical Reasoning
Six candidates D, J, K, L, N, V must be divided into two teams of three. K must be on the same team as N; V must be on the same team as K. D must be on the same team as L; J must be on the same team as D. Which set must form one complete team?
A. K, N, V
B. K, N, D
C. K, D, L
D. N, L, J
Correct Answer: A
Because K, N, and V must all be together and each team has three members, they form one team.
Why Students Like It

Built For Focused Exam Preparation

A clean learning system that keeps students practicing, improving, and coming back.

Instant Feedback

Students immediately know the correct answer and learn from explanations.

Real Exam Practice

Timed mock tests help users prepare for real exam pressure.

Weak Area Tracking

Performance insights help students focus on the topics that need attention.

Student Feedback

What Learners Say

Start Your Success Journey Today

Create your free account and begin practicing with confidence.

Create Free Account