CSS - PMS - CCE - PCS - Mathematics
Age Problems
Four years from now, a person's age will be 20% greater than the present age. What is the present age?
A. 17 years
B. 20 years
C. 22 years
D. 25 years
Correct Answer: B
Let present age be x. Then x + 4 = 1.20x. Therefore 0.20x = 4 and x = 20.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A person's age nine years from now will be three years more than twice the age six years ago. What is the present age?
A. 18 years
B. 15 years
C. 20 years
D. 23 years
Correct Answer: A
Let present age be x. Then x + 9 = 2(x - 6) + 3. Hence x + 9 = 2x - 9, so x = 18.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Eighteen years from now, a person's age will be three times the age six years ago. What is the present age?
A. 15 years
B. 20 years
C. 23 years
D. 18 years
Correct Answer: D
Let present age be x. Then x + 18 = 3(x - 6). Thus x + 18 = 3x - 18, so x = 18.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The ratio of a person's age ten years ago to the age fourteen years from now is 2:5. What is the present age?
A. 23 years
B. 28 years
C. 26 years
D. 31 years
Correct Answer: C
Let present age be x. Then (x - 10)/(x + 14) = 2/5. So 5x - 50 = 2x + 28, giving x = 26.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Five years ago, a person's age was three-fourths of the age seven years from now. What is the present age?
A. 37 years
B. 41 years
C. 44 years
D. 47 years
Correct Answer: B
Let present age be x. Then x - 5 = (3/4)(x + 7). Thus 4x - 20 = 3x + 21, giving x = 41.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Fifteen years from now, a person's age will be seven-fourths of the present age. What is the present age?
A. 20 years
B. 17 years
C. 22 years
D. 25 years
Correct Answer: A
Let present age be x. Then x + 15 = 7x/4. Hence 4x + 60 = 7x, so x = 20.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The ratio of a person's age four years ago to the age eight years from now is 3:5. What is the present age?
A. 19 years
B. 24 years
C. 27 years
D. 22 years
Correct Answer: D
Let the present age be x. Then (x - 4)/(x + 8) = 3/5. Thus 5x - 20 = 3x + 24, so x = 22.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Twelve years from now, a person's age will be five-thirds of the age six years ago. What is the present age?
A. 29 years
B. 36 years
C. 33 years
D. 39 years
Correct Answer: C
Let the present age be x. Then x + 12 = (5/3)(x - 6). Multiplying by 3 gives 3x + 36 = 5x - 30, so x = 33.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Eight years ago, a person's age was 60% of the present age. What is the present age?
A. 17 years
B. 20 years
C. 22 years
D. 25 years
Correct Answer: B
Let the present age be x. Then x - 8 = 0.60x. Hence 0.40x = 8 and x = 20.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
In 6 years, a person's age will be four-thirds of the present age. What is the present age?
A. 18 years
B. 15 years
C. 20 years
D. 23 years
Correct Answer: A
Let the present age be x. Then x + 6 = 4x/3. So 3x + 18 = 4x, giving x = 18.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A woman is six times as old as a child. After 12 years, she will be three times as old. What is the woman's present age?
A. 42
B. 48
C. 54
D. 36
Correct Answer: B
Let child's age=x and woman's age=6x. After 12 years: 6x+12=3(x+12). Thus 3x=24, x=8 and woman=48.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Three years ago, the ages of A and B were in the ratio 4:3. Nine years from now, they will be in the ratio 7:6. What is A's present age?
A. 16
B. 21
C. 18
D. 19
Correct Answer: D
Three years ago ages were 4x and 3x. Nine years from now they are 4x+12 and 3x+12. Their ratio 7:6 gives x=4, so A=19.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The average age of eight students is 15 years. When their teacher is included, the average becomes 18 years. What is the teacher's age?
A. 40
B. 36
C. 42
D. 45
Correct Answer: C
Students' total=8×15=120. New total=9×18=162. Teacher's age=42.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A father and his two sons have a total age of 90 years. The father is twice the combined age of the sons, whose ages are in the ratio 2:3. What is the elder son's age?
A. 18
B. 20
C. 12
D. 15
Correct Answer: A
Let sons' total=S and father=2S. Then 3S=90, S=30. Sons are 2:3, so elder=3/5×30=18.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
Ten years from now, a person will be twice as old as five years ago. What is the present age?
A. 15
B. 25
C. 20
D. 30
Correct Answer: C
Let present age=x. x+10=2(x−5). Thus x+10=2x−10 and x=20.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The present ages of A and B are in the ratio 3:5. After 9 years, the ratio will be 2:3. What is B's present age?
A. 36
B. 40
C. 50
D. 45
Correct Answer: D
Let ages be 3x and 5x. (3x+9)/(5x+9)=2/3. Hence 9x+27=10x+18, x=9 and B=45.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A mother is 30 years older than her daughter. After 5 years, the mother will be 2.5 times as old. What is the daughter's present age?
A. 12
B. 15
C. 10
D. 20
Correct Answer: B
Let daughter=x; mother=x+30. After 5 years: x+35=2.5(x+5). Solving gives x=15.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
A is twice as old as B. Eight years ago, A was three times as old as B. What is A's present age?
A. 32
B. 24
C. 36
D. 28
Correct Answer: A
Let B=x and A=2x. Eight years ago: 2x−8=3(x−8). Therefore x=16 and A=32.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The average age of a husband and wife is 35 years. When their child is included, the average becomes 24 years. What is the child's age?
A. 1
B. 2
C. 4
D. 6
Correct Answer: B
Husband and wife total=70. Family total=3×24=72. Child's age=2 years.
CSS - PMS - CCE - PCS - Mathematics
Age Problems
The ages of three siblings are in the ratio 3:4:5 and total 60 years. What will be their average age after 6 years?
A. 24
B. 28
C. 26
D. 20
Correct Answer: C
Present average=60/3=20. After 6 years, each age increases by 6, so average=26.